BIOL335 LOUNGE

A place for BIOL335 people to ask, answer and discuss questions, place their 'requests' and make suggestions

Monday, April 16, 2007

REVIEW SESSION: ROOM NUMBER FINALIZED

For those who are checking this before 10am, we finally have been assigned a room for the review session:

room 2361 in biosci (11-1pm).

There will be a note up in room 5458 for those who did not have a chance to see this.

9 Comments:

Anonymous Anonymous said...

"I am making up a set of 4 questions covering the yeast 2 hybrid system, assembling contigs, pedigrees with RFLPs and deficiency mapping. They should be ready for this weekend. The parallel site where I post notes and explanations is having technical problems and I can't access it to make changes or addition-hopefully they'll solve that.In the meantime, above is a practice question (T54 people: it's very slightly different from the one you got!)."

Pam, you wrote this in one of your blog entries way back. I was wondering if you had these questions online? Or if you read this before the tutorial, can you bring it tomorrow?

3:14 AM  
Anonymous Anonymous said...

They are all on this blog, except for the STS one that I could not get formattted properly.
One, for example, is the "FCD" question that people keep referring to in the comments. There's also a 2 hybrid question, a complementation/Df mapping analysis and a transposable elements question.
Check out the archive page relative to the week of March 11th (http://335lounge.blogspot.com/2007_03_11_archive.html)
three of the questions are there.

Also, our review session/extra tutorial was Monday, April 16th. I'll be in the help room, 2519, today (april 23) from 2 to 4 pm.

Cheers

Pam

9:23 AM  
Anonymous Anonymous said...

Whats the difference between complementation group and complementation genes?

8:00 PM  
Anonymous Anonymous said...

I don't know what complementation genes are. A complementation group is a group of mutants that do not complement each other.

For example, if you have 3 mutants, numbered 1 to 3, and all of them give you the same phenotype, but mutant 1 X mutant2 gives you a WT F1, while mutant 1 X mutant 3 gives you mutant F1, then you can say that mutant 1 and mutant 3 are in the same complementation group, while mutant 1 and mutant 2 are in different complementation groups (because they do complement each other).
We expect that mutant 2 X mutant 3 gives a WT F1.
So, we have here 3 mutants, representing 2 complementation groups: one complementation group contains mutants 1 and 3, the other one contains mutant 2.

Hope this helps

Cheers

Pam

10:15 PM  
Anonymous Anonymous said...

I am so scared :(

10:26 PM  
Anonymous Anonymous said...

have a good night sleep, a nutritious breakfast, go for a walk on the beach, and you'll be fine. The exam is very doable, really. Just a lot of reading (make sure you take your time to understand the questions), some thinking, and a little writing.

Good luck, everyone!

Pam

10:31 PM  
Anonymous Anonymous said...

It's here!!!! OMG...I sure hope the genetics Gods are with all of us today!!! It's raining outside...is this a sign of things to come??? :s

9:28 AM  
Anonymous Anonymous said...

Was anyone able to figure out 7C? I was doing great for time until I stumbled upon that question, I spent about 45 minutes and still couldn't figure it out. What did you all get?

5:43 PM  
Anonymous Anonymous said...

Good for people to know.

7:14 PM  

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